\[d = 0,6;\ \ \ \ \ S_{10} = 39:\]
\[S_{10} = \frac{2a_{1} + 9d}{2} \cdot 10 =\]
\[= \left( 2a_{1} + 9d \right) \cdot 5\]
\[10a_{1} + 45d = 39\]
\[10a_{1} = 39 - 45 \cdot 0,6\]
\[10a_{1} = 12\]
\[a_{1} = 1,2.\]
\[a_{6} = a_{1} + 5d = 1,2 + 3 = 4,2\]
\[Ответ:\ \ a_{1} = 1,2;\ \ \ a_{6} = 4,2.\]