\[x² + (a + 1)x + 1 = 0\]
\[D = a^{2} + 2a + 1 - 4 =\]
\[= a^{2} + 2a - 3 < 0\]
\[a^{2} + 2a - 3 = 0\]
\[a_{1} + a_{2} = - 2,\ \ \ a_{1} \cdot a_{2} = - 3\]
\[a_{1} = - 3,\ \ a_{2} = 1\]
\[Ответ:( - 3;1).\]