\[\frac{1}{\sqrt{33} + 1} =\]
\[= \frac{\sqrt{33} - 1}{\left( \sqrt{33} + 1 \right)\left( \sqrt{33} - 1 \right)} =\]
\[= \frac{\sqrt{33} - 1}{33 - 1} = \frac{\sqrt{33} - 1}{32}\]