4. \(\frac{a^9 \cdot a^8}{a^{12}}\) при \(a=2\)

\(\frac{a^9 \cdot a^8}{a^{12}} = \frac{a^{9+8}}{a^{12}} = \frac{a^{17}}{a^{12}} = a^{17-12} = a^5\). Подставим \(a=2\): \(2^5 = 32\).