Дана функция f(x)=-2x+1; x^2-7; 2. Найдите: f(7,6).

\[f(x) = \left\{ \begin{matrix} - 2x + 1,\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ x \leq - 4 \\ x^{2} - 7,\ \ - 4 < x < 3 \\ 2,\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ x \geq 3 \\ \end{matrix} \right.\ \]

\[f(7,6) = 2.\]