\[f(x) = 4x^{4} - 3x^{2} + 14;\]
\[f^{'}(x) = 16x^{3} - 6x;\]
\[f^{'}(5) = 16 \cdot 125 - 6 \cdot 5 =\]
\[= 2000 - 30 = 1970.\]