\[36x^{2} + \frac{1}{x^{2}} = 13;\ \ \ \ 6x + \frac{1}{x} = ?\]
\[36x^{2} + 12x \cdot \frac{1}{x} + \frac{1}{x^{2}} = 13 + 12x \cdot \frac{1}{x}\]
\[\left( 6x + \frac{1}{x} \right)^{2} = 13 + 12\]
\[\left( 6x + \frac{1}{x} \right)^{2} = 25\]
\[6x + \frac{1}{x} = 5;\]
\[6x + \frac{1}{x} = - 5.\]
\[Ответ:\ - 5;\ \ 5.\]