\[64x^{2} + \frac{1}{x^{2}} = 65\]
\[\left( 8x + \frac{1}{x} \right)^{2} = 64x^{2} + 16 + \frac{1}{x^{2}} =\]
\[= 64x^{2} + \frac{1}{x^{2}} + 16 =\]
\[= 65 + 16 = 81;\]
\[8x + \frac{1}{x} = \sqrt{81} = 9.\]
\[Ответ:9.\]