Какие из чисел -3; -2; 2; 3 являются корнями уравнения:

а) x^2 + 8 = 6x;

б) | x − 6| = 3 − 2x?

\[а)\ x^{2} + 8 = 6x\]

\[x^{2} - 6x + 8 = 0\]

\[x = - 3:\]

\[9 + 18 + 8 \neq 0.\]

\[x = - 2:\]

\[4 + 12 + 8 \neq 0.\]

\[x = 3:\]

\[9 - 18 + 8 = 0\]

\[- 1 \neq 0.\]

\[x = 2:\]

\[4 - 12 + 8 = 0\]

\[0 = 0\]

\[Ответ:x = 2.\]

\[б)\ |x - 6| = 3 - 2x\]

\[x = - 3:\]

\[| - 3 - 6| = 3 + 6\]

\[9 = 9.\]

\[x = - 2:\]

\[| - 2 - 6| = 3 + 4\]

\[8 \neq 7.\]

\[x = 3:\]

\[|3 - 6| = 3 - 6\]

\[3 \neq - 3.\]

\[x = 2:\]

\[|2 - 6| = 3 - 4\]

\[- 4 \neq - 1.\]

\[Ответ:x = - 3.\]