\[4,\ \ \ \ 4\frac{1}{3},\ \ \ \ b_{n},\ \ \ 5,\ \ldots;\]
\[d = 4\frac{1}{3} - 4 = \frac{1}{3};\]
\[a_{n} = 4 + \frac{1}{3} \cdot (n - 1) =\]
\[= 4 + \frac{1}{3}n - \frac{1}{3} = \frac{1}{3}n + 3\frac{2}{3};\]