Найдите корни уравнения: 4/(x+5)-3/(x-1)=26/(x^2+4x-5)-1.

\[\frac{4}{x + 5} - \frac{3}{x - 1} = \frac{26}{x^{2} + 4x - 5} - 1\]

\[x^{2} + 4x - 5 = 0\]

\[x_{1} + x_{2} = - 4;\ \ \ x_{1} \cdot x_{2} = - 5\]

\[x_{1} = - 5;\ \ \ x_{2} = 1.\]

\[x^{2} + 5x - 50 = 0\]

\[x_{1} + x_{2} = - 5;\ \ \ x_{1} \cdot x_{2} = - 50\]

\[x_{1} = - 10;\ \ \ x_{2} = 5.\]

\[Ответ:\ \ x = - 10;\ \ x = 5.\]