Найдите корни уравнения: 7·(1-x)=(2x+3)(1-x).

\[7 \cdot (1 - x) = (2x + 3)(1 - x)\]

\[7 \cdot (1 - x) - (2x + 3)(1 - x) =\]

\[= 0\]

\[(1 - x)\left( 7 - (2x + 3) \right) = 0\]

\[(1 - x)(7 - 2x - 3) = 0\]

\[(1 - x)(4 - 2x) = 0\]

\[1 - x = 0\ \ \ \ \ \ \ \ \ 4 - 2x = 0\]

\[x = 1\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ x = 2\ \]

\[Ответ:x = 1;\ \ x = 2.\]