Найдите множество решений неравенства: (x^2-9)/5-(x+1)/4>=(x-5)/2.

\[\frac{x^{2} - 9}{5} - \frac{x + 1}{4} \geq \frac{x - 5}{2}\ \ \ \ | \cdot 20\]

\[4x^{2} - 15x + 9 \geq 0\]

\[D = 225 - 144 = 81\]

\[x_{1} = \frac{15 + 9}{8} = 3\]

\[x_{2} = \frac{15 - 9}{8} = 0,75\]

\[Ответ:\ ( - \infty;0,75\rbrack \cup \lbrack 3;\ + \infty).\]