\[f(x) = \frac{x^{2} - 2x - 3}{x + 1},\ \ x \neq - 1\]
\[x^{2} - 2x - 3 = 0\]
\[x_{1} + x_{2} = 2,\ \ x_{1} \cdot x_{2} = - 3\]
\[x_{1} = - 1,\ \ x_{2} = 3\]
\[Ответ:\ - 1;\ \ 3.\]