\[a_{1} = 9;\ \ \ S_{10} = - 15:\]
\[S_{10} = \frac{{2a}_{1} + d(n - 1)}{2} \cdot 10 =\]
\[= \left( {2a}_{1} + 9d \right) \cdot 5 = (18 + 9d) \cdot 5\]
\[(18 + 9d) \cdot 5 = - 15\]
\[18 + 9d = - 3\]
\[9d = - 21\ \ \ \ \]
\[d = - \frac{7}{3}.\]
\[a_{13} = 9 + 12 \cdot \left( - \frac{7}{3} \right) =\]
\[= 9 - 28 = - 19.\]
\[Ответ:\ \ d = - \frac{7}{3};\ \ \ a_{13} = - 19.\ \]