\[\frac{\sqrt[4]{16x^{5}y^{4}}}{3y\sqrt[4]{x}} = \frac{\sqrt[4]{2^{4}x^{4}xy^{4}}}{3y\sqrt[4]{x}} =\]
\[x = 6;\ \ y = - \frac{2}{5}:\]
\[\frac{2|x||y|}{3y} = - \frac{2xy}{3y} =\]