\[\left\{ \begin{matrix} x^{2} + y^{2} = 1 \\ x + y = - 1\ \\ \end{matrix} \right.\ \]
\[\left\{ \begin{matrix} x = - 1 - y\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \\ ( - 1 - y)^{2} + y^{2} = 1 \\ \end{matrix} \right.\ \]
\[1 + 2y + y^{2} + y^{2} - 1 = 0\]
\[2y^{2} + 2y = 0\]
\[2y(y + 1) = 0\]
\[y_{1} = 0;\ \ \ y_{2} = - 1.\]
\[x_{1} = - 1 - 0 = - 1;\]
\[x_{2} = - 1 - ( - 1) = 0.\]
\[Ответ:( - 1;0);(0; - 1).\]