\[- 2 < a < - 1\ \ \ \ \ и\ \ \ 0 < b < 3\]
\[+ \left| \begin{matrix} 0 < \frac{1}{3}b < 1 \\ - 2 < a < - 1 \\ \end{matrix} \right.\ \ \]
\[\ \overline{\ \ \ - 2 < \frac{1}{3}b + a < 0}\]
\[Ответ:\ - 2 < \frac{1}{3}b + a < 0.\]