\[y = ax^{2} + bx + c\ \ \]
\[\text{M\ }(3;\ - 1) - вершина;\ \ K\ (1;3).\]
\[x_{0} = \frac{- b}{2a}\text{\ \ }\]
\[- \frac{b}{2a} = 3\ \ \]
\[b = - 6a.\]
\[ax^{2} - 6ax + c = 1;\ \ \ \ x_{0} = 3\]
\[9a - 18a + c = 1\]
\[- 9a + c = 1\]
\[c = 1 + 9a.\]
\[так\ как\ K\ (1;3):\]
\[a + b + c = 3\]
\[\ a - 6a + 1 + 9a = 3\]
\[4a = 2\ \ \]
\[a = 0,5.\]
\[b = - 6 \cdot 0,5 = - 3;\]
\[c = 1 + 9 \cdot 0,5 = 5,5.\]
\[Ответ:a = 0,5;\ \ b = - 3;\ \ \]
\[c = 5,5.\]