\[y = \frac{\left( x^{2} - 1 \right)\left( x^{2} - 9 \right)}{x^{2} - 2x - 3} =\]
\[= \frac{(x - 1)(x + 1)(x - 3)(x + 3)}{(x + 1)(x - 3)} =\]
\[= (x - 1)(x + 3) = x^{2} - x + 3x - 3 =\]
\[= x^{2} + 2x - 3\]
\[x^{2} - 2x - 3 = (x + 1)(x - 3)\]
\[x_{1} + x_{2} = 2;\ \ x_{1} \cdot x_{2} = - 3\]
\[x_{1} = 3;\ \ \ x_{2} = - 1.\]
\[y = x^{2} + 2x - 3;\ \ x \neq - 1;\ \ x \neq 3.\]
\[y = c\ имеет\ с\ графиком\ одну\ общую\]
\[точку\ при:\]
\[c = 12.\]
\[Ответ:12.\]