Постройте график функции: y=x^2-4x+5.

Question

\[y = x² - 4x + 5 \Longrightarrow ветви\ вверх\]

\[x_{0} = \frac{4}{2} = 2,\ \ \]

\[y_{0} = 4 - 8 + 5 = 1\]

\[(2;1).\]

\[x\]	\[0\]	\[1\]
\[y\]	\[5\]	\[2\]

Accepted Answer

\[y = x² - 4x + 5 \Longrightarrow ветви\ вверх\]

\[x_{0} = \frac{4}{2} = 2,\ \ \]

\[y_{0} = 4 - 8 + 5 = 1\]

\[(2;1).\]

\[x\]	\[0\]	\[1\]
\[y\]	\[5\]	\[2\]

Ответ: