Представьте в виде дроби: (-16x^2/27y^3)^2*(9y^2/8x^2)^3.

\[\left( \frac{- 16x^{2}}{27y^{3}} \right)^{2} \cdot \left( \frac{9y^{2}}{8x^{2}} \right)^{3} =\]

\[= \frac{2^{8}x^{4}}{3^{6} \cdot y^{6}} \cdot \frac{3^{6}y^{6}}{2^{9}x^{6}} = \frac{1}{2x^{2}}\]