\[y = 3x^{2} - 12x + a\]
\[\left\{ \begin{matrix} 3 > 0 \\ D < 0 \\ \end{matrix} \right.\ \]
\[D = 12^{2} - 4 \cdot 3 \cdot a = 144 - 12a\]
\[144 - 12a < 0\]
\[12a > 144\]
\[a > 12\]
\[Ответ:\ при\ a > 12.\]