\[y = (a + 1)x^{2} - 2x + 3\]
\[\left\{ \begin{matrix} a + 1 > 0 \\ D < 0\ \ \ \ \ \ \ \ \\ \end{matrix} \right.\ \text{\ \ \ \ \ \ }\]
\[D = 4 - 4 \cdot 3 \cdot (a + 1) =\]
\[= 4 - 12a - 12 = - 12a - 8\]
\[\left\{ \begin{matrix} a > - 1\ \ \ \ \ \ \ \ \\ - 12a < - 8 \\ \end{matrix} \right.\ \text{\ \ \ \ \ \ \ }\]
\[\left\{ \begin{matrix} a > - 1\ \ \ \ \ \\ 12a > - 8 \\ \end{matrix} \right.\ \text{\ \ \ \ }\]
\[\left\{ \begin{matrix} a > - 1 \\ a > - \frac{2}{3} \\ \end{matrix} \right.\ ;\ \ \ \ a > - \frac{2}{3}\]
\[Ответ:\ при\ a > - \frac{2}{3}.\]