\[\left( 5b^{2} + 7b \right)x = b\]
\[x = \frac{b}{b(5b + 7)};\ \ b \neq 0\]
\[x = \frac{1}{5b + 7};\ \ 1 > 0\]
\[5b + 7 > 0\]
\[5b > - 7\]
\[b > - \frac{7}{5}\]
\[Ответ:( - 1,4;0) \cup (0; + \infty).\]