\[\sqrt{4x + 16} + \frac{1}{\sqrt{6 - 3x}}\]
\[\left\{ \begin{matrix} 4x + 16 \geq 0 \\ 6 - 3x > 0\ \ \ \\ \end{matrix} \right.\ \Longrightarrow \left\{ \begin{matrix} 4x \geq - 16 \\ 3x < 6\ \ \ \ \ \ \\ \end{matrix} \right.\ \Longrightarrow\]
\[\Longrightarrow \left\{ \begin{matrix} x \geq - 4 \\ x < 2\ \ \ \ \\ \end{matrix} \right.\ \]
\[Ответ:\lbrack - 4;2).\]