\[\frac{x - 8}{3x^{2} - 10x + 3} = \frac{x - 8}{(x - 3)(3x - 1)}\]
\[ОДЗ:\ x \neq 3;\ x \neq \frac{1}{3}\]
\[3x^{2} - 10x + 3 = 0\]
\[D_{1} = 25 - 9 = 16\]
\[x_{1} = \frac{5 + 4}{3} = 3;\ \ \ \ \ \]
\[x_{2} = \frac{5 - 4}{3} = \frac{1}{3}.\]
\[3x^{2} - 10x + 3 = 3 \cdot (x - 3)\left( x - \frac{1}{3} \right) =\]
\[= (x - 3)(3x - 1).\]
\[Ответ:x - любое\ число,\ \]
\[\ \ \ \ \ \ \ \ \ \ \ \ кроме\ x = 3;x = \frac{1}{3}.\]