\[(5t)^{2} - 6^{2} \geq (5t - 4)^{2}\]
\[25t^{2} - 36 \geq 25t^{2} + 16 - 40t\]
\[16 - 40t + 36 \leq 0\]
\[40t \geq 52\]
\[t \geq \frac{13}{10}\]
\[t \geq 1,3\]
\[t = 2 \Longrightarrow наименьшее\]
\[целое\ число.\]
\[Ответ:t \in \lbrack 1,3;\ + \infty);\ \ t = 2.\]