\[\sqrt{3x - 2} + \sqrt{6 - x}\]
\[\left\{ \begin{matrix} 3x - 2 \geq 0 \\ 6 - x \geq 0\ \ \\ \end{matrix} \right.\ \]
\[\left\{ \begin{matrix} 3x \geq 2 \\ x \leq 6\ \ \\ \end{matrix} \right.\ \]
\[\left\{ \begin{matrix} x \geq \frac{2}{3} \\ x \leq 6 \\ \end{matrix} \right.\ \]
\[Ответ:\frac{2}{3} \leq x \leq 6.\]