\[2 + y - 0,5y^{2} = 2y^{2} - 3y\]
\[2,5y^{2} - 4y - 2 = 0\]
\[D = b^{2} - 4ac =\]
\[= 16 - 4 \cdot 2,5 \cdot ( - 2) =\]
\[= 16 + 20 = 36\]
\[y_{1} = \frac{4 + 6}{5} = \frac{10}{5} = 2\]
\[y_{2} = \frac{4 - 6}{5} = - \frac{2}{5} = - 0,4\]
\[Ответ:при\ y = 2\ \ и\ \ \ y = - 0,4.\]