\[x² - 4x - 32 = 0\]
\[x_{1} + x_{2} = 4;\ \ \ \ x_{1} \cdot x_{2} = - 32\]
\[x_{1} = 8;\ \ \ \ \ \ \ \ \ \ \ \ \ \ x_{2} = - 4\]
\[x^{2} - 4x - 32 = (x - 8)(x + 4).\]