Вопрос:

Решите графически уравнение: 4x^(-2)=x+3.

Ответ:

\[4x^{- 2} = x + 3\]

\[\left\{ \begin{matrix} y = 4x^{- 2}\ \\ y = x + 3 \\ \end{matrix} \right.\ \text{\ \ \ \ \ \ \ \ }\left\{ \begin{matrix} y = \frac{4}{x^{2}}\text{\ \ \ \ } \\ y = x + 3 \\ \end{matrix} \right.\ \]

\[y = \frac{4}{x^{2}}\]

\[x\] \[1\] \[2\] \[3\] \[- 1\] \[- 2\] \[- 3\]
\[y\] \[4\] \[1\] \[\frac{4}{9}\] \[4\] \[1\] \[\frac{4}{9}\]

\[y = x + 3\]

\[x\] \[- 2\] \[0\] \[1\]
\[y\] \[1\] \[3\] \[4\]

\[Ответ:\ \ ( - 2;1);\ \ (1;\ \ 4).\]

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