Решите методом подстановки систему уравнений x-2y=14; 2x+5y=1.

\[\left\{ \begin{matrix} x - 2y = 14 \\ 2x + 5y = 1 \\ \end{matrix} \right.\ \Longrightarrow \left\{ \begin{matrix} x = 14 + 2y\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \\ 2 \cdot (14 + 2y) + 5y = 1 \\ \end{matrix} \right.\ \]

\[28 + 4y + 5y = 1\]

\[9y = - 27\]

\[y = - 3.\]

\[x = 14 + 2y = 14 + 2 \cdot ( - 3) = 14 - 6 = 8.\]

\[\left\{ \begin{matrix} x = 8\ \ \ \\ y = - 3 \\ \end{matrix} \right.\ \]

\[Ответ:(8;\ - 3).\]