\[- 3x^{2} + 4x + 4 \leq 0\]
\[3x^{2} - 4x - 4 \geq 0\]
\[D_{1} = 4 + 12 = 16\]
\[x_{1} = \frac{2 + 4}{3} = 2;\ \]
\[x_{2} = \frac{2 - 4}{3} = - \frac{2}{3}.\]
\[\left( x + \frac{2}{3} \right)(x - 2) \geq 0\]
\[x \leq - \frac{2}{3};\ \ x \geq 2.\]
\[Ответ:x \leq - \frac{2}{3};\ \ x \geq 2.\]