Решите неравенство 1,7-2*(3x-1)>0,3-4x

\[\ 1,7 - 2 \cdot (3x - 1) > 0,3 - 4x\]

\[1,7 - 6x + 2 > 0,3 - 4x\]

\[- 2x > - 3,4\]

\[x < 1,7.\ \]

\[3 - 4c < \frac{6 - 5c}{5}\ \ \ \ | \cdot 5\]

\[5 \cdot (3 - 4c) < 6 - 5c\]

\[15 - 20c < 6 - 5c\]

\[- 15c < - 9\]

\[c > \frac{3}{5}\]

\[c > 0,6.\]

\[\ \left\{ \begin{matrix} 6 - 2x > 1\ \ \ \\ 3x + 1 < 13 \\ \end{matrix} \right.\ \text{\ \ \ \ \ }\left\{ \begin{matrix} - 2x > - 5 \\ 3x < 12\ \ \ \ \\ \end{matrix} \right.\ \text{\ \ \ \ \ }\left\{ \begin{matrix} x < 2,5 \\ x < 4\ \ \ \\ \end{matrix} \right.\ \]

\[Ответ:x \in ( - \infty;2,5)\text{.\ }\]