Решите неравенство: (2x+3)(3x-4)/(x-1)<=0.

\[\frac{(2x + 3)(3x - 4)}{x - 1} \leq 0\]

\[\frac{6 \cdot (x + 1,5)\left( x - 1\frac{1}{3} \right)}{x - 1} \leq 0\]

\[Ответ:( - \infty; - 1,5\rbrack \cup \left( 1;1\frac{1}{3} \right\rbrack.\]