Решите неравенство: 2x^2+7x-4>0.

\[2x^{2} + 7x - 4 > 0\]

\[D = 49 + 32 = 81\]

\[x_{1} = \frac{- 7 + 9}{4} = \frac{1}{2} = 0,5;\]

\[x_{2} = \frac{- 7 - 9}{4} = - 4;\]

\[2(x + 4)(x - 0,5) > 0\]

\[x < - 4;\ \ \ x > 0,5.\]

\[Ответ:x < - 4;x > 0,5.\]