Решите неравенство: (x+14)/6-(x-12)/8<=3.

\[\frac{x + 14}{6} - \frac{x - 12}{8} \leq 3\ \ \ \ \ | \cdot 24\]

\[4x + 56 - 3x + 36 \leq 72\]

\[x \leq - 20\]

\[Ответ:( - \infty;\ \left. \ - 20 \right\rbrack.\]