Решите неравенство (x+2)(x-1)(3x-7)<=0.

\[(x + 2)(x - 1)(3x - 7) \leq 0\]

\[x = - 2;\ \ x = 1;\ \ x = \frac{7}{3} = 2\frac{1}{3}\]

\[Ответ:x \in ( - \infty; - 2\rbrack \cup \left\lbrack 1;2\frac{1}{3} \right\rbrack.\]