Решите неравенство: (x^2+2x)(4x-2)>=0.

\[\left( x^{2} + 2x \right)(4x - 2) \geq 0\]

\[4x(x + 2)\left( x - \frac{1}{2} \right) \geq 0\]

\[Ответ:\lbrack - 2;0\rbrack \cup \lbrack 0,5; + \infty).\]