Решите неравенство: x^2>2,3x;

\[\ x² > 2,3x\]

\[x^{2} - 2,3x > 0\]

\[x(x - 2,3) = 0\]

\[x = 0\ \ \ \ \ \ \ x - 2,3 = 0\]

\[\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ x = 2,3\]

\[Ответ:\ \ x \in \ ( - \infty;0) \cup (2,3;\ + \infty).\]