Решите неравенство: x^2>4,7x;

\[\ x² > 4,7x\]

\[x^{2} - 4,7x > 0\]

\[x(x - 4,7) > 0\]

\[x(x - 4,7) = 0\]

\[x = 0\ \ \ \ \ \ \ \ x - 4,7 = 0\]

\[\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ x = 4,7\]

\[Ответ:\ x \in ( - \infty;0) \cup (4,7; + \infty).\]