Решите неравенство: (x^2-14x+48)/(x-7)^2<0.

Ответ:

\[\frac{x^{2} - 14x + 48}{(x - 7)^{2}} < 0\]

\[x^{2} - 14x + 48 = 0\]

\[D = 49 - 48 = 1\]

\[x_{1} = 7 + 1 = 8;\ \ \ x_{2} = 7 - 1 = 6.\]

\[\frac{(x - 6)(x - 8)}{(x - 7)²} < 0\]