Решите неравенство: (x^3-x^2-4x+4)/(x-1)<=0.

\[\frac{x^{3} - x^{2} - 4x + 4}{x - 1} \leq 0\]

\[\frac{x^{2}(x - 1) - 4 \cdot (x - 1)}{x - 1} \leq 0\]

\[\frac{(x - 1)(x^{2} - 4)}{x - 1} \leq 0\]

\[\frac{(x - 1)(x - 2)(x + 2)}{x - 1} \leq 0\]

\[Ответ:\lbrack - 2;1) \cup (1;2\rbrack.\]