Решите неравенство: ((x-2)/(x-3))^2+((x+2)/(x+3))^2>(2x^2-8)/(x^2-9).

\[\left( \frac{x - 2}{x - 3} \right)^{2} + \left( \frac{x + 2}{x + 3} \right)^{2} > \frac{2x^{2} - 8}{x^{2} - 9}\]

\[\left( \frac{x - 2^{\backslash x + 3}}{x - 3} - \frac{x + 2^{\backslash x - 3}}{x + 3} \right)^{2} > 0\]

\[\left( \frac{2x}{(x + 3)(x - 3)} \right)^{2} > 0\]

\[\frac{4x^{2}}{(x + 3)^{2}(x - 3)^{2}} > 0\]