Решите неравенство: (x-3)/(3-x)<=1/6.

\[\frac{x - 3}{3 - x} \leq \frac{1}{6}\]

\[- \left( \frac{x - 3}{x - 3} \right) \leq \frac{1}{6}\]

\[x \neq 3,\ \ - 1 < \frac{1}{6}\]

\[Ответ:( - \infty;\ 3) \cup (3;\ + \infty).\]