Решите неравенство: (x-3)/4+x/3>=2.

\[\frac{x - 3}{4} + \frac{x}{3} \geq 2\ \ \ | \cdot 12\]

\[3x - 9 + 4x \geq - 24\]

\[7x \geq 33\]

\[x \geq 4\frac{5}{7}\]

\[Ответ:\ \left\lbrack 4\frac{5}{7}; + \infty \right).\]