Решите систему неравенств: 5x^2-16x+3>0; x<=7.

\[\left\{ \begin{matrix} 5x² - 16x + 3 > 0 \\ x \leq 7\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \\ \end{matrix} \right.\ \]

\[5x^{2} - 16x + 3 = 0\]

\[D = 256 - 60 = 196\]

\[x_{1} = \frac{16 + 14}{10} = 3\]

\[x_{2} = \frac{16 - 14}{10} = \frac{1}{5} = 0,2\]

\[Ответ:( - \infty;0,2) \cup (3;7\rbrack.\]