Решите систему неравенств 7-3x<1; 1,8-x<1,9

\[\ \left\{ \begin{matrix} 7 - 3x < 1\ \ \ \ \\ 1,8 - x < 1,9 \\ \end{matrix} \right.\ \text{\ \ \ \ \ }\left\{ \begin{matrix} - 3x < - 6 \\ - x < 0,1 \\ \end{matrix}\text{\ \ \ \ \ \ \ } \right.\ \]

\[\left\{ \begin{matrix} x > 2\ \ \ \ \ \ \ \\ x > - 0,1 \\ \end{matrix} \right.\ \]

\[Ответ:\ \ x \in (2;\ + \infty).\]

\[\ |2x + 3| = 7\]

\[2x + 3 = 7\]

\[2x = 4\]

\[x = 2\]

\[2x + 3 = - 7\]

\[2x = - 10\]

\[x = - 5\]

\[Ответ:\ \ x = - 5\ \ и\ \ x = 2.\]