Решите систему неравенств6 (7-5x)/2<=-4; x^2-4x<0.

\[\left\{ \begin{matrix} \frac{7 - 5x}{2} \leq - 4 \\ x^{2} - 4x < 0 \\ \end{matrix} \right.\ \]

\[\left\{ \begin{matrix} 7 - 5x \leq - 8 \\ x(x - 4) < 0 \\ \end{matrix} \right.\ \]

\[\left\{ \begin{matrix} 5x \geq 15\ \ \ \ \ \ \ \ \ \\ x(x - 4) < 0 \\ \end{matrix} \right.\ \]

\[\left\{ \begin{matrix} x \geq 3\ \ \ \ \ \ \ \ \\ 0 < x < 4 \\ \end{matrix} \right.\ \]

\[3 \leq x < 4.\]